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Compound Interest

8 questions · Hard

Compound interest is paid on the principal plus the interest already earned. Amount = P × (1 + R/100)^T, and CI = amount − principal.

💡 Quick tricks

  1. For 2 years, CI − SI = P × (R/100)².
  2. At 10% a year, the amount grows by 1.1 times each year: 1.21 times after 2 years.
  3. Half-yearly compounding: halve the rate and double the number of periods.
8 questions

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  1. Q1Hard

    Compound interest on ₹13,800 for 2 years at 10% a year?

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    Answer: D. ₹2,898

    💡 Amount = 13,800 × (1 + 10/100)² = ₹16,698, so CI = ₹2,898.

  2. Q2Hard

    Compound interest on ₹1,700 for 2 years at 20% a year?

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    Answer: C. ₹748

    💡 Amount = 1,700 × (1 + 20/100)² = ₹2,448, so CI = ₹748.

  3. Q3Hard

    Compound interest on ₹21,600 for 2 years at 15% a year?

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    Answer: B. ₹6,966

    💡 Amount = 21,600 × (1 + 15/100)² = ₹28,566, so CI = ₹6,966.

  4. Q4Hard

    Compound interest on ₹7,100 for 2 years at 10% a year?

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    Answer: C. ₹1,491

    💡 Amount = 7,100 × (1 + 10/100)² = ₹8,591, so CI = ₹1,491.

  1. Q5Hard

    Compound interest on ₹15,000 for 2 years at 12% a year?

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    Answer: D. ₹3,816

    💡 Amount = 15,000 × (1 + 12/100)² = ₹18,816, so CI = ₹3,816.

  2. Q6Hard

    Compound interest on ₹18,800 for 2 years at 20% a year?

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    Answer: C. ₹8,272

    💡 Amount = 18,800 × (1 + 20/100)² = ₹27,072, so CI = ₹8,272.

  3. Q7Hard

    Compound interest on ₹12,000 for 2 years at 5% a year?

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    Answer: D. ₹1,230

    💡 Amount = 12,000 × (1 + 5/100)² = ₹13,230, so CI = ₹1,230.

  4. Q8Hard

    Compound interest on ₹30,000 for 2 years at 20% a year?

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    Answer: C. ₹13,200

    💡 Amount = 30,000 × (1 + 20/100)² = ₹43,200, so CI = ₹13,200.

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